Tuesday, 3 April 2018

Study 145

Árpád Rusz
Problem Paradise
2017

White wins

1. Bxf3! Rxg5! 1... Rxf3 2. g6 Rf1+ 3. Ka2 Rf8 4. g7 Ra8+ 5. Kb3! echo 5... Kd3 6. Kb4 Rb8+ 7. Ka5 Kc4 8. Be5 Re8 9. Kb6! +- (9. Bd6? Rg8 10. Bf8 Rxg7! 11. Bxg7 Kxc5 =) 2. c6 Ke3

3. Bh1! Rg1+ 4. Kc2!! echo 4. Ka2? Rxh1 5. c7 Rc1 =; 4. Kb2? Rxh1 5. c7 Rh8 = 4... Rxa1 4... Rxh1 5. c7 chameleon echo 5... Rh8 6. Bxh8 +- 5. c7 chameleon echo 5... Ra8 6. Bxa8 +-

Thursday, 18 January 2018

Study 144

Árpád Rusz
The Problemist
2018

Draw

1. Bxd7! 1. Nc5+? Kd5 2. Nxd7 Nxd6 3. Nf6+ Kc5! 4. Nd7+ Bxd7 5. Bxd7 Position X' 5... d3 -+ 1... Bxd7 2. Nc5+ The knight leaves the b3 square, but it will return there after a long trip. 2... Kd5 3. Nxd7 Nxd6 3... Kxd6 4. Nb6 d3 5. Nc4+ Kc5 6. Nd2 = 4. Nf6+! 4. Nb6+? Kc6 -+ 4... Ke6 4... Kc5 5. Nd7+ Position X - The knight proves to be more efficient than the bishop in the fight against the passed pawn. 5... Kd5 (5... Kc6 6. Ne5+ Kd5 7. Nd3 =) 6. Nf6+ Kc5 (6... Kc4 7. Ng4 d3 8. Ne5+ =) 7. Nd7+ perpetual check 5. Nh5! This extra file was missing from the other flank. 5... Kf5 5... d3 6. Nf4+ = 6. Ng3+ Kg4 7. Nf1! The knight has to stop the pawn before it reaches d2. 7. Ne2? d3 8. Nc3 d2 -+ 7... Kf3 8. Nd2+ Ke2 9. Nb3! = During the trip, the knight drew a big square on the board!

Tuesday, 16 January 2018

Study 143

Árpád Rusz
Joiţa MT
2018

White wins

The a4 pawn prevents a simple win (1.Rf4 followed by 2.Ra4#). In order to win, white will try to reach the same position but without the a4 pawn. But how does the "disappearing pawn magic trick" work?

1. Bf3! Logical try: 1. Rf4? Rd6! -+; 1. f3? Rf1! = 1... Rd4 1... Bxf3 2. Rxf3


Saavedra's double attack (echo)

2... Rh1 3. Ra3#; 1... Rd6 2. Rxd6 Bf5+ 3. Rd3! +- 2. Kc3! 2. Bxg4? Rxg4 3. Rxh6 Rg8 4. Ra6 Ra8 = 2... Rxa4 3. Kb3 Bd7! 3... Rd4 4. Bxg4 Rxg4 5. Rc6 Kb1 6. Rxc7 +- 4. Bc6! Rd4 4... Bxc6 5. Rxc6


Saavedra's double attack (echo)

5... Rxa5 6. Rc1# 5. Kc3! 5. Bxd7? Rxd7 6. Rxh6 Rd8 = 5... Rd1 6. Kc2 Bg4 We are back to the initial position but the a4 pawn has disappeared! 6... Rd4 7. Bxd7 Rxd7 8. Rf4! +-


The a4 pawn has disappeared!

7. Rf4! Rd6 8. Ra4#

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Related study: Saavedra 1

Friday, 5 January 2018

Study 142

Árpád Rusz
Krug-50 JT
2017
1st Special Prize
- after Bourzutschky & Konoval -

White wins

Try: 1. Rc6+? Kd7 In the following two variations black saves the game by sacrificing the knight or the rook. This provides some comfort for the fact that in the actual mainline these two black pieces are captured on their initial squares. 1... Ke7? 2. Ne3! knight sacrifice 2... Nxe3 3. Kxf4 +- 2. Rc5 2. Ne5+ Ke7 3. Nxd3 cxd3 4. Bxd3 Nxb4! knight sacrifice (4... Rf3? 5. Be4 Rg3+ 6. Kh4 Rxc3 7. Bxd5 +-) 5. cxb4 Rxb4 = 2... Rxg4+! rook sacrifice 3. Kxg4 Nf6+ 4. Kf4 Nxh7 4... Bxh7? 5. Ke5! Ng4+ 6. Kd4 +- 5. b5 Nf8! 6. Ke5 Ng6+ 7. Kf6 Kd6 8. Rc6+ Kd7 9. Rc5 Kd6 positional draw

Solution: 1. Bg8+ Kd6 2. Rc6+! rook sacrifice (2. Bxd5? Rf5+ 3. Kh4 Kxc7 =) 2... Kxc6 3. Bxd5+ Kd6! The black king triangulates! (3... Kxd5 4. Kxf4 black is in zugzwang Be2 (4... Ke6 5. Ne5 Be2 6. Ke4 +-) 5. Ne3+ Ke6 6. Ke4 +-) 4. Kxf4 Kxd5


1st cyclic zugzwang - WTM

In order to win, white must reach the same position but with black to move. The shortest manoeuvre to pass the move to black lasts 35 moves! All moves from the cycle are unique optimal moves. 5. Ne3+ (5. Nf2?! Be2 6. Kf5?! Bd3+ 7. Kf6? Bc2! 8. Ke7 Ba4 =) 5... Ke6 6. Nd1 Kd5 7. Nb2 White threatens to bring the knight to c5. 7... Bc2! 8. Kg5 Bd3 (8... Ke4 9. Kf6 Kd5 10. Ke7 Bf5 11. Kd8 +-) 9. Kf6 (9. Na4? Ke5 =) 9... Kd6 White should bring the knight to a5 before he continues the king manoeuvre. 10. Nd1! (The shortest path to a5 via a4-c5-b7 doesn't work: 10. Na4?! Be4 11. Nc5 Bc6!; If the king starts the manoeuvre too soon, its knight gets stuck on b2: 10. Kf7?! Bf1 11. Ke8 Be2 12. Kd8 Kc6! 13. Ke7 Kb5! Now, in order to win, white has to free its knight... 14. Ke6 Bg4+ 15. Ke5 Bf3 16. Kf4 Be2 17. Ke3 Bh5 18. Kd2 Bg6 19. Ke2! Quicker than the immediate 18.Nd1. It is better to lure the bishop to f5 first using a triangulation. 19... Bh5+ 20. Ke3 Bg4 21. Kd2 Bf5 22. Nd1 Now the knight is free but also the black king! 22... Kc6 23. Ke3 Kd5 24. Nb2 Bg6 25. Kf4 Bc2 and we have returned to a previous position from the main line) 10... Be4 11. Ne3 Bd3 12. Ng4 Be2 13. Ne5 Bd3 14. Nf7+ Kd5 This move blocks the a8-h1 diagonal allowing the knight to go to b7. (14... Kd7 15. Ke5 +-) 15. Nd8! Kd6 16. Nb7+ Kc7 17. Na5! (Moving immediately to c5 is wrong: 17. Nc5?! Kd6 and the white king cannot move to f5.) 17... Kd6 18. Kf7 Kd7 19. Nb7! Black is in zugzwang! 19... Be2 (The bishop cannot move to the big diagonal: 19... Be4 20. Nc5+ +-) 20. Kf6 Kc7 21. Nc5 Kd6 22. Kf5 The bishop was not on d3! 22... Kd5 23. Kf4 Bf1 This is a new cyclic zugzwang position! (23... Bd3 24. Nxd3 cxd3 25. Ke3 Kc4 26. Kd2 +-)


2nd cyclic zugzwang - WTM

White will lose a tempo by a square-shaped manoeuvre (Nc5-d7-f6-e4-c5) while the black king triangulates (Kd5-d6-e6-d5). 24. Nd7 (It is too early to bring the knight to a4: 24. Na4? Be2 25. Ke3 Bd3 White is in zugzwang! 26. Nb6+ Kc6 27. Nc8 Kc7 28. Ne7 Kd6 29. Ng8 Ke5) 24... Kd6 25. Nf6 Ke6 26. Ne4 Kd5 27. Nc5


2nd cyclic zugzwang - BTM

27... Be2 28. Na4! Bd3 29. Ke3 Black is in zugzwang! The bishop has to leave the good square from which it controls the b1-h7 diagonal. 29... Bf1 30. Nb6+ Ke5 (In the following variation we can see the drawback of leaving the b1-h7 diagonal: 30... Kc6 31. Nc8 Kc7 32. Ne7 Kd6 33. Ng6! Kd5 (33... Bd3 34. Nf4 +-) 34. Kf2 Bd3 35. Nf4+ Ke4 36. Nxd3 Kxd3 37. b5 +-) 31. Kf3! This is a waiting move to lure the bishop to d3! (The immediate Nd7 is refuted by Ke6. 31. Nd7+?! Ke6) 31... Bd3 32. Nd7+ Kd6 (Ke6 is not that strong anymore: 32... Ke6 33. Nc5+ Kd5 34. Nxd3 cxd3 35. Ke3 Kc4 36. Kd2 +-) 33. Nc5 By attacking the bishop, white wins a crucial tempo. The black king cannot go back to the fifth rank, so the bishop must control e4. That means it has to leave the d3-f1 diagonal. 33... Bf5 The bishop also takes under control the important d7 square. 34. Kf4! (34. Ke3?! would throw away all the progress we have done so far. Ke5 M111 35. Na4 Bd7 36. Nb2 Be6 37. Kd2 Bd5 38. Nd1 Be4 39. Ne3 Bd3 40. Ng4+ Kf4 41. Nf6 Bf5 42. Nd5+ Ke4 43. Ne3 Be6 44. Nc2 Bg4 45. Nd4 Ke5 46. Kc1 Kd6 47. Kc2 Bh5 48. Nf5+ Ke5 49. Ne3 Bf7 50. Kb2 Ke4 51. Nc2 Bh5 52. Nd4 Kd5 53. Ka3 Bd1 54. Nf5 Kc6 55. Ne3 Bb3 56. Kb2 Kc7 $1 57. Nf5 Ba4 58. Kc1 Kd7 59. Nh6 Kd6 60. Kd2 Ke5 61. Ke3 Bd1 62. Nf7+ Ke6 63. Ng5+ Ke5 64. Ne4 Bc2 65. Nd2 Bd3 66. Nf3+ Kd5 67. Nh2 Bc2 68. Kf4 Bb1 $1 69. Ng4 Bd3 and we have returned to the cyclic zugzwang position from the main line) 34... Bg6 35. Ke3 Kd5 (35... Ke5 36. Nd7+ now that the bishop has left f5 this move works Kd5 37. Nb6+ +-) 36. Nd7 The threat is Nb6+ 36... Bd3 37. Nf6+ Ke5 38. Ng4+ Kd5 39. Kf4 +-


1st cyclic zugzwang - BTM

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This study is based on the following computer endgame which is the longest win for KNPPKBP:

M. Bourzutschky & Y. Konoval
EG#188
2012

"For the KNPPKBP endgame the longest win is 102 moves and there is only one record position." 1. Na3 Kg2 2. Nb5 c6 3. Nd4 c5 4. Nb5 Kg3 5. Nc7 Bc8 6. Na8 Ba6 7. Nb6 Kf4 8. Nd7 c4 9. b4 Bb5 10. Nc5 Ke5 11. Nb7 Bc6 12. Na5 Bb5 13. Kb2 Kd5 14. Nb7 Bc6 15. Nd8 Kd6 16. Nf7+ Ke6 17. Nh6 Ke5 18. Kc2 Bd5 19. Ng4+ Kf4 20. Nf2 Bf3 21. Kc1 Kf5 22. Kd2 Ke5 23. Ke3 Bg2 24. Nd1 Bh3 25. Kd2 Bf5 26. Ne3 Bd3 27. Ng4+ Kf4 28. Nf6 Bf5 29. Nd5+ Ke4 30. Ne3 Be6 31. Nc2 Bg4 32. Nd4 Ke5 33. Kc1 Kd6 34. Kc2 Bh5 35. Nf5+ Ke5 36. Ne3 Bf7 37. Kb2 Ke4 38. Nc2 Bh5 39. Nd4 Kd5 40. Ka3 Bd1 41. Nf5 Kc6 42. Ne3 Bb3 43. Kb2 Kc7 44. Nf5 Ba4 45. Kc1 Kd7 46. Nh6 Ke6 47. Kd2 Ke5 48. Ke3 Bd1 49. Nf7+ Ke6 50. Ng5+ Ke5 51. Ne4 Be2 52. Nd2 Bd3 53. Nf3+ Kd5 54. Nh2 Be4 55. Kf4 Bg6 56. Ng4 Bd3 57. Ne3+ Ke6 58. Nd1 Bc2 59. Nb2 Kd5 60. Kg5 Bd3 61. Kf6 Kd6 62. Nd1 Be4 63. Ne3 Bd3 64. Ng4 Be2 65. Ne5 Bd3 66. Nf7+ Kd5 67. Nd8 Kd6 68. Nb7+ Kc7 69. Na5 Kd6 70. Kf7 Kd7 71. Nb7 Be2 72. Kf6 Kc7 73. Nc5 Kd6 74. Kf5 Kd5 75. Kf4 Bf1 76. Nd7 Kd6 77. Nf6 Ke6 78. Ne4 Be2 79. Nc5+ Kd5 80. Na4 Bd3 81. Ke3 Bf1 82. Nb6+ Ke5 83. Kf3 Bd3 84. Nd7+ Kd6 85. Nc5 Bf5 86. Kf4 Bg6 87. Ke3 Kd5 88. Nd7 Bd3 89. Nf6+ Ke6 90. Ng4 Kd5 91. Kf4 Be2 92. Ne3+ Kc6 93. Kf5 Bd3+ 94. Ke5 Kb6 95. Nf5 Kb7 96. Nd4 Ka6 97. Ke6 Be4 98. Nf5 Bc6 99. Nd6 Ba4 100. Ke5 Bb3 101. Kd4 Kb6 102. Nxc4+ +- "Attention, please! After 9.b4!! White has to make 92 moves without moving a pawn and capturing. A surprising example of a 50 move rule exception!"

Study 141

Árpád Rusz
Krug-50 JT
2017
Commendation

White wins

1. Nc5 h2 2. Ne4 Kf4 2... h1=Q 3. Ng3+ +- 3. Nf2 Kf3 4. Nh1 Kg2 5. Ke3 Kxh1 6. Kf2 c5 7. d3 a4 8. Bb2

a. 8... c4 9. dxc4 9. d4? c3! 10. Bxc3 a3 11. Ba1 a2 12. d5 stalemate 9... a3 10. Ba1! echo 10. Bxa3? stalemate

10... a2 11. Kg3 Kg1 12. Bd4+ Kh1 13. Kh3! 13. c5 a1=Q 14. Bxa1 Kg1 15. Bd4+ Kh1! -+ 13... a1=Q 14. Bxa1 Kg1 15. Bd4+ Kh1 16. Be5 Kg1 17. Bxh2+ +-

b. 8... a3 9. Bxa3 c4 10. d4! 10. dxc4? stalemate 10... c3 11. Bc1! echo

11... c2 12. Kg3 Kg1 13. Be3+ Kh1 14. Kh3! c1=Q 15. Bxc1 Kg1 16. Be3+ Kh1 17. Bf4 Kg1 18. Bxh2+ +-

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Study 140

Árpád Rusz
Krug-50 JT
2017
Commendation

Draw

1. h7 Nf5! Black doesn't capture the c2 pawn anticipating a NN/P endgame with a harmful pawn! 1... Nxc2 2. h8=Q Bxd4+ 3. Qxd4 Nxd4 4. Nxb4! Nxb4 = 2. h8=Q Bxd4+ fork 3. Qxd4 Nxd4 4. Nxb4! 4. c4? bxc3 e.p. -+; 4. Kb7? Nc3! 5. Nxb4 Kxb4 -+ 4... Nxb4


refusal to fork

5. c4!! 5. c3? fork 5... Nbc6+! (5... Ndc6+? 6. Ka8! Nd3 7. c4 Nc5 stalemate) 6. Ka8!? (6. Kb7 Nd8+ 7. Kc7 N4c6! 8. c4 Ka6 9. c5 Ka7 -+ The white king cannot reach a8, the only safe corner if the pawn is blocked on c5.) 6... Ne6 7. c4 Ka6! Black doesn't block the pawn and lets it pass the Troitzky line! (7... Nc5? stalemate) 8. c5 Nc7# 5... Ne6 6. c5! Now it is too late to stop the pawn because it has passed the Troitzky line. 6... Nc6+ 7. Kb7 (or 7. Ka8 Kb5 8. Kb7 Ned8+ 9. Ka8) 7... Ned8+ 8. Ka8! White still has to be very careful! Even if the pawn has passed the Troizky line, a8 is the only safe corner. 8... Ne6 8... Kb5 stalemate 9. Kb7 Ned4 10. Ka8! positional draw - fortress 10. Kc7? Ka6 -+

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Saturday, 16 December 2017

Study 139

Árpád Rusz
Magyar Sakkvilág
2017

Draw

1. Nc2+ Kb1 2. Nd4 2. Nb4? Qb3# 2... Qc4 2... Qd5? 3. Rf1# 3. Rb6+ Ka1

4. Rb3!! mutual zugzwang 4. Rb4? Qa2# 4... axb3 4... Qxd4 5. Rb1+! Kxb1 stalemate; 4... Qc5+ 5. Rb4 Qc3+ 6. Kxa4 = 5. Nxb3+ Kb1 6. Nd2+ =

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Wednesday, 13 December 2017

Study 138

Árpád Rusz
Zadachy i Etyudy
2017

White wins

1. Bg7+ White cannot capture the a1 bishop immediately because the f8 bishop is also hanging: 1. Kxa1? Rxf8 = 1... Kd5 2. Bxa1! 2. Kxa1? fails because the bishop from g7 would become again a good target for the rook. 2... f2 3. Ng3! Rf5! 4. Be2 Rg5 5. Nf1 Rxg7 = 2... f2 3. Ng3! 3. Nxf2? Rxf2 = 3... f1=Q+ 4. Nxf1 Rxf1+

5. Kb2!! A surprising move which closes the bishop on the corner. Thematic try: 5. Ka2? Rxa1+! with check 6. Kxa1 Kc4 = 5... Rxa1 without check! 5... Kc4 6. Be2+ +-; 5... Re1 6. Bf7+ Kc6 7. Bc4 +-; 5... Rf5 6. Bd1 Kc4 7. Ka3 Rf1 8. Be2+ +- 6. Bf7+! 6. Kxa1? Kc4 = 6... Kc6 7. Be8+! 7. Kxa1? Kb5 = 7... Kd5 8. Kxa1 Kc4 9. b5! +-

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Tuesday, 12 December 2017

Study 137

Árpád Rusz & Martin Minski
JPA-85 JT
2017
Special Commendation

White wins

1. a7! Qd8! 1... Qxa7 2. Bf7+ Kd7 (2... Ke7 3. Nc6+ +-) 3. Qa4+ Kc7 4. Qc6+ Kb8 5. Qe8+ Kc7 6. Qxe5+ Kb6 7. Nc4+ +-; 1... b1=Q 2. Qxb1 (2. axb8=Q+? Qxb8 3. Nc6 Qc7 4. Qa8+ Kd7 5. Qf8 Be6+ =) 2... Qxb1 3. a8=Q+ +- 2. a8=Q 2. a8=R? Bc8 3. Ra7 Bd7 (3... Qg5+? 4. Rg7 +-) 4. Ra8 Bc8 positional draw 2... Be6+! 3. Kg7! 3. Bxe6? Qxa8 = 3... Qxa8 4. Qa4+ 4. Bxe6? Ke7! 5. Bg4 Qf8+ =; 4. Bxa8?? Bxa2 -+ 4... Bd7

5. Nc6!! Cross Theme 5. Qb3? b1=Q! (5... Qxa5? 6. Qb8+ Qd8 (6... Ke7 7. Qf8#) 7. Bf7+ Ke7 8. Qxe5+ Be6 9. Qxe6#) 6. Qxb1 Qxd5 = 5... Qxa4 5... Bxc6 6. Bxc6+ +-; 5... Qxc6 6. Bxc6 b1=Q 7. Qa8+ Ke7 8. Qf8+ +- 6. Bf7#

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Study 136

Árpád Rusz
JPA 85 JT
2017
Special Honourable Mention

Draw

Black has twice as much material than white so it looks very natural to start with a queen promotion: 1. e8=Q? a2 2. Rf6+ Kg2+ 3. Kc2 3. Kc4 Ra4+! 4. Qxa4 Rh4+ -+ 3... a1=N+! Black chooses to promote the pawn to a knight! 3... Rc3+? 4. Kd2 Rd5+ 5. Ke2 Rc2+ 6. Ke3 Rc3+ 7. Ke2 =

Variation A:

4. Kb2 Rb3+ 5. Kc1 Rc5+ 6. Kd2 6. Kd1 Rb1+ 7. Ke2 Rc2+ 8. Kd3 Rd1+ 9. Ke3 Re1+ -+ 6... Rc2+ 7. Kd1 Rb1#


echo checkmate
Variation B:

4. Kd1 Rh1+ 5. Kd2 Ra2+ 6. Kd3 Rd1+ 7. Kc3 Rc2+ 8. Kb4 Rb1+ 9. Ka3 Rb3+ 10. Ka4 Ra2#


echo checkmate

Let's go back to the initial position of the study.


The actual solution starts with a surprising sacrifice: 1. Rh6!! a2! 1... Rxh6 2. e8=Q a2 3. Qf7+! (3. Qf8+? Kg2 4. Qg7+ (4. Qxh6 a1=Q -+) 4... Rg6 5. Qb2+ Kh3 6. Qc3+ Rg3 -+) 3... Kg2 4. Qb7+! Kg1 5. Qg7+ Rg6 6. Qd4+ = 2. Rxh3+ Kg2

3. Rh1!! 3. e8=Q? a1=Q 4. Qe4+ Kxh3 5. Qf3+ Kh4 6. Qf4+ Kh5 -+ 3... Kxh1 3... Re5 4. Ra1 Rxe7 5. Rxa2+ Kg3 6. Ra5 Rc7 7. Rd5! Kg4 8. Rd4+ Kg5 9. Rd5+ Kg6 10. Rd6+ Kg7 11. Rd5! Rc6 12. Kb4! Kg6 13. Kb5 Rc8 14. Rd6+ Kg5 15. Rd5+ Kg4 16. Rd4+ Kg3 17. Rd3+ (17. Rd5? Rh8 -+) 17... Kg4 18. Rd4+ Kg5 19. Rd5+ Kg6 20. Rd6+ perpetual check) 4. e8=Q Finally, the pawn promotes to a queen. 4... a1=Q 5. Qe4+ Kh2 6. Qh4+ Kg2 7. Qg4+ Kf2 8. Qf4+ Ke2 9. Qe4+ Kd2 9... Kf2 10. Qf4+ Kg2 11. Qg4+ Kh2 12. Qh4+ perpetual check 10. Qd4+! Qxd4 stalemate

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Monday, 11 December 2017

Study 135

Árpád Rusz
Sachova Skladba
2017

Draw

1. Nf7 1. Nxg6? Bxg6 2. f5 Bxf5 -+ 1... Kb7 2. Ne5 Bf5 3. Nc4 Kc6! 3... a2 4. Kb2 = 4. Nxa3 Kc5 5. Kb2! 5. Nc2? Bxc2 6. Kxc2 Kc4! zz (6... Kd4? 7. f5! gxf5 8. Kd2 zz Ke4 9. Ke2 zz Kf4 10. Kf2 zz Kg4 11. Kg2 zz f4 12. Kf2 f3 13. Kf1 Kg3 14. Kg1 zz f2+ 15. Kf1 zz Kf3 stalemate) 7. Kd2 Kd4 8. Ke2 Ke4 9. Kf2 (9. f5 gxf5 -+) 9... Kxf4 10. Kg2 Kg4! (10... g5? 11. Kf2 Kg4 12. Kg2 Kh4 13. Kh2 g4 14. Kg2 g3 15. Kg1 Kh3 16. Kh1 g2+ 17. Kg1 Kg3 stalemate) 11. Kh2 Kf3 12. Kh3 g5 13. Kh2 g4 14. Kg1 Kg3! 15. Kh1 Kf2 -+ 5... Kb4

6. Ka1!! mutual zugzwang. Thematic try: 6. Ka2? Be4! mutual zugzwang 7. Kb2 Bd3! -+ mutual zugzwang 6... Be4 6... Kxa3 stalemate 7. Ka2! Bd3 8. Kb2 Bf5 9. Ka1! positional draw - fortress


corresponding squares(K/B)

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Study 134

Árpád Rusz
Dvoretsky MT
2017
Commendation

White wins

1. a7 Kf1! Black avoids moving to f3 because that square is on the long diagonal. 2. Re7! Logical try: 2. Re8? c4 3. Rb8 Rb3! 4. Rxb3 cxb3 5. Kb8 b2 6. a8=Q No check! b1=Q+ = 2... Kf2 Now white has to lose a tempo.


cyclic zugzwang - WTM

3. Rb7 Ra5 4. Rc7! 4. Kb8? Ke3 5. Rc7 Kd4 = 4... Rb5 4... Ke3 5. Kb7 Kd4 6. Rc6! (6. Kb6? Ra1 7. Rxc5 Rxa7! =) 6... Rxa7+ 7. Kxa7 +- 5. Re7 White has transferred the move to black.


cyclic zugzwang - BTM

5... Kf3 Now it was unavoidable for the black king to step on the long diagonal. 5... Kf1 6. Rb7 Ra5 7. Rb2/Kb8 +- 6. Re8! Now that the black king was lured to f3 the main plan works! 6... c4 6... Kf2 7. Rb8 Ra5 8. Kb7 Ke3 9. Rc8 Kd3!? 10. Rxc5! +- (10. Kb6? Rxa7 11. Kxa7 c4 =) 7. Rb8 Rb3 8. Rxb3+ cxb3 9. Kb8 b2 10. a8=Q+ +- The queen has promoted with check!

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Thursday, 9 November 2017

Study 133

Árpád Rusz
Internet (RCS blog)
2017

Draw (DUPLEX)

Although at first glance the initial position seems like a mutual zugzwang, there is a way to achieve draw.
1. Nf2! Thematic try: 1. Ng3? Bxg3 2. Bd8 Bxf4 3. Bf6 Bc1 4. Bxg7+ Kxg7 5. f4 Bxb2+! -+; 1. Be1? Bxe1 2. Nf2 Nc7/Nb6 3. Nh3 Bh4 4. Ng5 Bxg5 5. fxg5 Nb5/Nd5 6. f4 Nc3! 7. bxc3 dxc3 -+ 1... Bxf2 2. Bd8 Be3 3. Bf6! Bc1 3... gxf6 4. exf6 = 4. Bxg7+! Kxg7 5. h8=Q+ 5. h8=R? Bxb2+! -+ 5... Kxh8 6. g7+ Kh7 7. g8=Q+ Kxg8 stalemate

If black is to move in the initial position we have a similar solution. The only move that draws is 1... Nc7! Thematic try: 1... Nb6?

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Thursday, 2 November 2017

Study 37a

V. Vlasenko
Malyshko-105 MT
2017

White wins

Thematic try: 1. Rf8+? Kg2 2. Rg6+ Kh1 3. Rf1+ Qg1 4. Ra1! Qxa1 5. Bxa1 c3+ 6. Kc1 c2 =

With the rook on g6, the g7 square cannot be used as a cutting point to avoid stalemate and there is no time for the critical move Rg6-g8.

Solution: 1. Rf6+! Kg2 2. Rg8+ Kh1 3. Rf1+ Qg1 4. Ra1! 4. Ke2? Qxf1+ 5. Kxf1 stalemate 4... Qxa1 5. Bxa1 c3+ 6. Kc1! mutual zugzwang 6. Bxc3? stalemate 6... c2 This time the rook is already on its right place so the stalemate can be avoided!


pseudo-Indian

7. Bg7! Kg2 8. Be5+ +-

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Related studies: Study 37

Wednesday, 1 November 2017

Study 132

Árpád Rusz
Moscow Ty
2017
1st Prize

White wins

1. Ke4! Kc1! 1... Rh1 2. Rxg2 Rxh3 3. Kxf4 Rh1 4. Rf2 +- 2. Kf3 Rh1 3. Kxg2! f3+! 4. Kxf3

In this position, black has to natural continuations:

a. 4... Rxh3+


dual avoidance

5. Kg4! 5. Ke4? Rg3! 6. Kf4 Rd3! 7. Rf2 (7. Re7 Rd1! 8. Rxf7 Rf1+ =) 7... Rd2! 8. Rf3 (8. Rxd2 Kxd2 9. Kf5 Ke3 10. Kf6 Kf4 =; 8. Rf1+ Kc2 9. Ke5 Rg2 10. Kf6 Kd3 11. Rf5 Ke4 =) 8... Rd7 9. Ke5 Kd2! 10. Kf6 Rd5! (10... Ke2? 11. Rf5 Ke3 12. Kg7 Ke4 13. Rxf7 Rxf7+ 14. Kxf7 Kf5 15. g6 +-) 11. Rf5 Rxf5+ 12. Kxf5 Ke3 13. Kf6 Kf4 = 5... Kd1! counter-attack 5... Rh7 6. Kf5 Kd1 7. Re5! +- The white rook has managed to defend the pawn from the fifth rank.

6. Re6!! Thematic try: 6. Re7? Rh7 7. Kf5 Rg7 8. Kf6 Rg6+ 9. Kf5 Rg7 = Positional draw. Attacking the black pawn with Re7 fails because black has the Rg7 defence. In the main line white will try to attack the black pawn from the opposite direction by bringing its rook to h7. To conquer the h-file, white has to bring its rook to h6 on the shortest way. That is the reason for the surprising sacrifice on e6!; 6. Rf2? Rh7 7. Kf5 Ke1 8. Ra2 Rh3! 9. Kg4 (9. Ra7 Rf3+ 10. Kg4 Rf2! =) 9... Rh7 10. Kf5 Rh3 positional draw; 6. Kxh3? Kxe2 = 6... Rh7! 6... fxe6 7. Kxh3 +-; 6... Rh1 7. Rf6 Rg1+ 8. Kf5 Rf1+ 9. Ke5 Rg1 10. Rf5 Ke2 11. Kf6 +- 7. Rh6! Rg7 7... Rxh6 8. gxh6 +- 8. Kf5 Ke2 9. Kf6 Rg8 10. Rh7! 10. Rh5? Kf3 11. Kxf7 Kg4! = counter-attack 10... Rg6+ 10... Kf3 11. Rxf7 Kg4 12. g6 Kh5 13. Rh7+ +- 11. Kf5 +- In contrast with the thematic try, black has no more the move Rg7 to defend.


But what if, before it captures the h3 pawn, black inserts a king move?

b. 4... Kd1!? 5. Rf2! We already know from the thematic try that 5. Re7? doesn't win: 5... Rxh3+ 6. Kg4 Rh7 7. Kf5 Rg7 8. Kf6 Rg6+ 9. Kf5 Rg7 positional draw 5... Rxh3+ 5... Ke1 6. Kg2! +-


dual avoidance

6. Ke4! Now 6. Kg4? will fail: 6... Rh7 7. Kf5 Ke1 8. Rf4 The white rook couldn't move to the fifth rank to defend the pawn. 8... Rg7! 9. Kf6 Rg6+! 10. Kf5 Rg7 positional draw 6... Rg3! 6... Rh7 7. Ke5! The white king avoids blocking the f5 square. 7... Ke1 8. Rf5! +- The white rook has managed to defend the pawn on the fifth rank. 7. Kf4 Rg1 8. Ra2! Rf1+ 9. Ke4! 9. Ke3? Rf5 = 9... Re1+ 10. Kd3! Re5 11. Ra1# Surprisingly, 4... Kd1!? also had a negative effect: the black king became exposed to a checkmate attack!

Watch this study on a dynamic board! Click here!

Study 131

Árpád Rusz
Selivanov-50 JT
2017
3rd Prize

White wins

1. d7 Nd5! 1... Ba4 2. Nc6! +-; 1... Bf5 2. Ne6! +- 2. Ne6! Thematic try: 2. Nc6? Nc7+ 3. Kb6 Ne6 (position X') 4. Nd4! Ba4! = 2... Nb4+ 3. Kb6 Nc6!


position X


position X'

If we compare Position X with Position X' from the thematic try, it appears like the two knights were "repainted". This is the only difference between the two positions so the study features the WCCT-10 Theme in an original way!

4. Nd4! 4. Kxc6? Ba4+ = 4... Bf5! Black goes for a stalemate trap! 4... Nd8 5. Nxc2 +- 5. Nxf5 5. Nxc6? Bxd7 = 5... Nb8! 6. d8=B! +- 6. d8=Q? stalemate

The end position has a white bishop and knight vs. a black knight, while in the initial position of the study there was a white knight vs. black bishop and knight. It looks like during the game, paradoxically, all minor pieces were repainted!

Watch this study on a dynamic board! Click here!